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Sagot :
[tex]\\ \tt\hookrightarrow p(2)=3(2)^6-5(2)^5-2+7[/tex]
[tex]\\ \tt\hookrightarrow p(2)=3(64)-5(32)+5[/tex]
[tex]\\ \tt\hookrightarrow p(2)=192-160+5[/tex]
[tex]\\ \tt\hookrightarrow p(2)=32+5[/tex]
[tex]\\ \tt\hookrightarrow p(2)=37[/tex]
Option B is correct
Answer:
B. 37
explanation:
Just replace x with the given value unit.
→ p(x)= 3x^6 - 5x^5 - x + 7
→ p(2)= 3(2)^6 - 5(2)^5 - (2)+ 7
→ p(2) = 3(64) - 5(32) - 2 + 7
→ 192 - 160 - 2 + 7
→ 37
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