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enlargements question- 20 POINTS :)

Enlargements Question 20 POINTS class=

Sagot :

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Answer:

x = 6.5 cm

Explanation:

make a equation to solve enlargements:

ST = 5 cm, QR = 7 cm, PS = x cm, PR = x + 2.6 cm

[tex]\frac{x}{5} = \frac{x+2.6}{7}[/tex]

7(x) = 5(x+2.6)

7x = 5x + 13

7x - 5x = 13

2x = 13

x = 6.5 cm

Answer:

x = 6.5

Step-by-step explanation:

Δ TPS and Δ QPR are similar ( AA postulate ) , so the ratios of corresponding sides are in proportion, that is

[tex]\frac{PS}{PR}[/tex] = [tex]\frac{TS}{QR}[/tex] ( substitute values )

[tex]\frac{x}{x+2.6}[/tex] = [tex]\frac{5}{7}[/tex] ( cross- multiply )

7x = 5(x + 2.6) ← distribute parenthesis

7x = 5x + 13 ( subtract 5x from both sides )

2x = 13 ( divide both sides by 2 )

x = 6.5

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