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A body falls from rest with an acceleration of 10m/s square . what is the velocity after 5s ? how far had it fallen by then?

Sagot :

SonamDendup123idn

Answer:

to answer the first part of the question.

what is the velocity after 5s.

a=(v-u)/t

a=10m/s²

u=0m/s( initial velocity)

t=5s

10m/s²=(v-0m/s²)/5s

10m/s²×5s=v-0m/s²

50m/s=v

the velocity after 5s will be 50m/s

to answer the second question we use the newton's second equation of linear motion, that is

S=(displacement)

S=ut+0.5at²

S=0m/s²×5s+0.5×10m/s²×(5s)²

S=0.5×10m/s²×(5s)²

S=5m/s²×(25s²)

S=125m

it had fallen 125m from where it was thrown.

HOPE IT HELPED,

PLEASE MARK BRAINLIEST

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