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The enthalpy of combustion gives the heat released during the combustible compound reacting to give incombustible substance. The energy released will be -1268 kJ.
What is the enthalpy of combustion?
The combustible compounds and substances react in the presence of oxygen to give the incombustible compound are called the heat of combustion.
The reaction can be shown as:
[tex]\rm 2C_{6}H_{6}(g) + 15O_{2}(g) \rightarrow 12CO_{2}(g) + 6H_{2}O(g)[/tex]
We know that the molar enthalpy of combustion of benzene [tex](\rm C_{6}H_{6})[/tex] = -3170 kJ/mol
From the equation above,
1 mole of benzene [tex](\rm C_{6}H_{6})[/tex] undergoing combustion = -3170 kJ/mol
So, 0.4 moles of benzene = X energy
Solving for X:
[tex]\begin{aligned}\rm X &= 0.4 \times -3170\;\rm kJ\\\\&= -1268\;\rm kJ\end{aligned}[/tex]
Therefore, -1268 kJ of energy will be released.
Learn more about the heat of combustion here:
https://brainly.com/question/2929270
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