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A projectile is fired with an initial speed of 55 m/s. If it lands at a distance 300 m from the original firing point, at what angle is the projectile fired

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The angle at which the projectile was fired is 38.19°.

What is a projectile?

A projectile is an object that is fired or lunched during a parabolic or curved motion.

To calculate the angle of projection of the projectile,  we use the formula below.

Formula:

  • R = U²sin2∅/g.............. Equation 1

Where:

  • R = Distance from the point where the projectile was fired to the point where its land
  • U = Initial velocity
  • g = acceleration due to gravity
  • ∅ = angle of projection.

make ∅ the subject of the equation

  • ∅ = [sin⁻¹(gR/U²)]/2.................. Equation 2

From the question,

Given:

  • R = 300 m
  • U = 55 m
  • g = 9.8 m/s²

Substitute these values into equation 2

  • ∅ = [sin⁻¹(9.8×300/55²)]/2
  • ∅ = [sin⁻¹(0.9719)]/2
  • ∅ = 76.385/2
  • ∅ = 38.19°

Hence, the angle at which the projectile was fired is 38.19°.

Learn more about projectile here: https://brainly.com/question/1130127


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