Answered

Join the IDNLearn.com community and start exploring a world of knowledge today. Our community provides accurate and timely answers to help you understand and solve any issue.

The means and mean absolute deviations of the individual times of members on two 4 times 400 meter relay track teams are shown in the table below. Means and Mean Absolute Deviations of Individual Times of Members of 4 times 400 meter Relay Track Teams Team A Team B Mean 59. 32 s 59. 1 s Mean Absolute Deviation 1. 5 s 2. 4 s What percent of Team B’s mean absolute deviation is the difference in the means? 9% 15% 25% 65%.

Sagot :

Percentage is a way to show the part of a whole. The percent of Team B’s mean absolute deviation is the difference in the means is 9%.

What is the percentage?

The percentage is a way to show a part of a whole. for example, one-fourth of area A can be written like 25% of A(0.25A.)

Given to us

Mean and Mean Absolute Deviation of Team A: 59.32 sec, 1.5 sec

Mean and Mean Absolute Deviation of Team B: 59.1 sec, 2.4 sec


As it is given in the problem we need to find the percent of Team B’s mean absolute deviation is the difference in the means, therefore,

[tex]Percentage = \dfrac{\text{Mean of Team A - Mean of Team B}}{\text{Mean Absolute Deviation of Team B}} \times 100[/tex]

Substitute the values,

[tex]Percentage = \dfrac{59.32 - 59.10}{2.4}\times 100 = 9.166\% \approx 9\%[/tex]

Hence, the percent of Team B’s mean absolute deviation is the difference in the means is 9%.

Learn more about Percentage:

https://brainly.com/question/8011401

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find precise solutions at IDNLearn.com. Thank you for trusting us with your queries, and we hope to see you again.