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A piece of tin foil has a volume of 0.645 mm3. If the foil measures 10.0 mm by 12.5mm, what is the thickness of the foil

Sagot :

Asuwafohjamesidn

The thickness of the foil is 0.00516 mm.

To calculate the thickness of the foil using the formula of volume of a cuboid.

Formula:

  • V = LWn................ Equation 1

Where:

  • V = Volume of the foil
  • L = Length of the foil
  • W = Width of the foil
  • n = Thickness of the foil.

Make n the subject of the equation

  • n = V/LW.............. Equation 2

From the question,

Given:

  • V = 0.645 mm³
  • L = 10.0 mm
  • W = 12.5 mm

Substitute these values into equation 2

  • n = (0.645)/(10×12.5)
  • n = 0.645/125
  • n = 0.00516 mm

Hence, The thickness of the foil is 0.00516 mm.
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