HayaRizidn
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pls help!! need it fast.... I'm stuck
[tex]2 log_{10}(5) + 3 log_{10}(2) - log_{10}(2) [/tex]
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Sagot :

Answer:

So this is also going to stay the same, multiply first, divide, then you have your answer. Make sure if needed you need to round up your numbers.

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Use power rule first:

\[tex]\log_{10}(5^2)+\log_{10}(2^3)-\log_{10}(2)[tex]

Now use product and quotient rule (if + in front inside goes on top and if - in front inside goes on bottom)

[\tex]\log_{10}(\frac{5^22^3}{2})[tex]

Reducing inside fraction;

[\tex]\log_{10}(5^22^2)[tex]

Simplifying inside:

[\tex]\log_{10}(100)[tex]

100 is a power of 10...that is 10^2=100 so final answer is 2.

[tex]\log_{10}(100)=2[\tex]

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