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What must the charge (sign and magnitude) of a particle of mass 1.44 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 680 N/C

Sagot :

Answer:

Q E = m g      electric and gravitational forces balance - both E and g are taken as positive in the downward direction

Q = m g / E = .00144 kg * 9.8 m/s^2 / 680 N/C = 2.08E-5 coul

This is the charge required for the specified force

Therefore Q = -2.08-5 C      for the charge to remain stationary

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