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Which is a zero of the quadratic function f(x) = 4x2 + 24x + 11?

x = –9.25
x = –5.5
x = 0.5
x = 3.25

Sagot :

Stephanianava71idn
X=-5.5 the other zero would be x=-0.5 but that’s not an option.
Lhannearaujoidn

One of the zeros of the given quadratic function is x=-5.5.

What is a Quadratic Function?

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

For solving a quadratic function you should find the discriminant: [tex]D=b^2-4ac[/tex]  . And after that you should apply the discriminant in the formula: [tex]x=\frac{-b\pm \sqrt{D} }{2a}[/tex]

In this equation:

a=4

b=24

c=11

  • STEP 1 - Find the discriminant (D)

[tex]D=b^2-4ac=24^2-4\cdot \:4\cdot \:11}=576-176=400[/tex]

  • STEP 2 - Find x

[tex]x_{1,\:2}=\frac{-b\pm \sqrt{D} }{2a}\\ \\ x_{1,\:2}=\frac{-24\pm \sqrt{24^2-4\cdot \:4\cdot \:11}}{2\cdot \:4}\\ \\ x_{1,\:2}=\frac{-24\pm \sqrt{400}}{8}\\ \\ x_{1,\:2}=\frac{-24\pm 20}{8}[/tex]

Then,

[tex]x_1=\frac{-24+20}{2\cdot \:4}\\ \\ x_1=\frac{-4}{8}=\frac{-1}{2}=-0.5[/tex]

and

[tex]x_2=\frac{-24-20}{2\cdot \:4}\\ \\ x_1=\frac{-44}{8}=\frac{-11}{2}=-5.5[/tex]

Read more about the quadratic function here:

brainly.com/question/1497716

Read more about the quadratic function here:

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