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Find the slope of the tangent line to k(x)=–2x at x=3.

Find The Slope Of The Tangent Line To Kx2x At X3 class=

Sagot :

Answer:

[tex]-2[/tex]

Step-by-step explanation:

[tex]k(x)=-2x\\k'(x)=-2\\k'(3)=-2[/tex]

What I basically did here was take the derivative of the function to find the slope of the function at any given point. Since -2x has a slope of -2, no matter what x is, the slope will always be -2.