Answer:
F) [tex]380\frac{4}{7}ft^2[/tex]
Step-by-step explanation:
Find the area of each part
Area of right triangle: [tex]A=\frac{1}{2}bh=\frac{1}{2}(6)(18)=(3)(18)=54ft^2[/tex]
Area of rectangle: [tex]A=bh=(12)(18)=216ft^2[/tex]
Area of left triangle: [tex]A=54ft^2[/tex] (this is because both triangles are congruent)
Area of semicircle: [tex]A=\frac{1}{2}\pi r^2=\frac{1}{2}(\frac{22}{7})(\frac{12}{2})^2=\frac{22}{14}(6)^2=\frac{11}{7}(36)=56\frac{4}{7}ft^2[/tex]
Add up all the areas
[tex]A=54ft^2+216ft^2+54ft^2+56\frac{4}{7}ft^2=380\frac{4}{7}ft^2[/tex]
