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What is the derivative of y= (x^2+4x+6)^5?

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Konrad509idn
[tex] y= (x^2+4x+6)^5\\ y'=5(x^2+4x+6)^4\cdot(2x+4)\\ y'=10(x+2)(x^2+4x+6)^4[/tex]
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