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Sagot :

Answer: A=2, B=5, C=4

Step-by-step explanation:

[tex]\frac{6x^{2}+13x-5}{x^{2}-16} \cdot \frac{x+4}{3x-1}\\\frac{(3x-1)(2x+5)}{(x-4)(x+4)} \cdot \frac{x+4}{3x-1}\\\frac{2x+5}{x-4}[/tex]

So A=2, B=5, and C=4.