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What is an equation of the line that passes through the points (5,-3) and
(-3, -3)?

Sagot :

Lolersgaming1idn

Answer:

y=-3

Step-by-step explanation:

First, you want the slope.

The slope is

[tex]\frac{-3-(-3)}{-3 - 5} = \frac{0}{-8}\\[/tex]

0/-8 = 0, so the line is horizontal.

the y-intercept must be -3 because it never changes.

So the equation must be

y=-3
  • (5,-3)
  • (-3,-3)

Slope:-

[tex]\\ \rm\hookrightarrow m=\dfrac{-3+3}{-3-5}=0[/tex]

Equation of line in point slope form

[tex]\\ \rm\hookrightarrow y+3=0(x-5)[/tex]

[tex]\\ \rm\hookrightarrow y+3=0[/tex]

[tex]\\ \rm\hookrightarrow y=-3[/tex]

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