IDNLearn.com: Where your questions meet expert advice and community support. Ask any question and get a thorough, accurate answer from our community of experienced professionals.
Sagot :
Answer:
4
Step-by-step explanation:
[tex]\lim_{x \to \infty}\frac{1-cos4x}{1-cos2x}= \lim_{x \to 0} \frac{(1-cos4x)'}{(1-cos2x)'}= \lim_{x \to 0}\frac{4sin4x}{2sin2x}= \lim_{x \to 0}\frac{2*2sin2xcos2x}{sin2x}\\ = \lim_{x \to 0}4cos2x\\ =4[/tex]
{L'Hospital's rule}
I hope this helps you
:)
We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.