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The distance of the yacht from the ship is found by accurately drawing
the relative location of the three vessels.
Response:
The given parameters are;
Distance of the tugboat from the ship, a = 28 km
Bearing of tugboat from the ship = 315°
Distance of the yacht from the tugboat, b = 21 km
Bearing of the yacht from the = 210°
Using a scale of 1 : 350,000, we have;
[tex]The \ drawing \ of \ a = \mathbf{\dfrac{28,000}{350,000} }= 0.08[/tex]
The length of a in the drawing = 0.08 m = 8 cm
[tex]The \ drawing \ of \ b = \mathbf{\dfrac{21,000}{350,000}} = 0.06[/tex]
Which gives;
b in the drawing = 0.06 m = 6 cm
Using the above dimensions and directions, the drawing of the relative
location of the three vessels can be accurately created using MS Word.
From the application, the vector form of the distance, d, of the ship from the yacht is presented as follows;
Which gives;
d = √(8.655² + 0.445²) = 8.67
Which gives;
Actual distance = 0.0867 m × 350,000 = 30,345 m = 30.345 km ≈ 30 km
Using cosine rule, where the angle formed at the tugboat = 75°, we have;
d² = 28² + 21² - 2 × 28 × 21 × cos(75°) ≈ 920.63
Which gives;
d ≈ √(920.63) ≈ 30
The distance of the yacht from the ship, d ≈ 30 km
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