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A 750 kg roller coaster car drops from rest at a height of 90 m along a frictionless track. What is velocity of the roller coaster at the top of a second hill that is 60 m high? Show work

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The velocity of the roller coaster at the top of the second hill is 24.25 m/s.


What is velocity?

Velocity is the rate of change of displacement. The s.i unit is m/s

To calculate the velocity of the coaster car, we use the formula below.

Formula:

  • mg(H-h) = mv²/2............... Equation 1

Where:

  • m = mass of the coaster car
  • H = Height of drop
  • h = Height of the second hill
  • v = velocity of the roller coaster.

From the question,

Given:

  • m = 750 kg
  • H = 90 m
  • h = 60 m
  • g = constant = 9.8 m/s²

Substitute these values into equation 1

  • 750(9.8)(90-60) = 750(v²)/2

Solve for v

  • 375v² = 220500
  • v² = 220500/375
  • v² = 588
  • v = √588
  • v = 24.25 m/s

Hence, The velocity of the roller coaster at the top of the second hill is 24.25 m/s.

Learn more about velocity here: https://brainly.com/question/24445340

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