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Sagot :
The diameter of Christy's pool is 4 times larger than the other .-.
How to find the relation between the radius of each pool?
We know that for a circle of radius R the area is given by:
A = π*R^2
Let's say that:
- R is the radius of Christy's pool
- R' is the radius of Emily's pool.
Then we have the corresponding areas.
- A = π*R^2
- A' = π*R'^2
We know that:
A = 16*A'
Replacing the equations, we get:
π*R^2 = 16*(π*R'^2)
R^2 = 16*R'^2
If we apply the square root in both sides, we get:
√R^2 = √(16*R'^2)
R = 4*R'
This means that the radius of Christy's pool is 4 times larger than the one of Emily's pool.
And the same is for the diameter (twice the radius).
D = 2*R
D' = 2*R'
Then:
D = 2*R = 2*(4*R') = 4*(2*R') = 4*D'
The diameter of Christy's pool is 4 times larger than the other diameter.
If you want to learn more about circles, you can read:
https://brainly.com/question/25306774
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