Explore IDNLearn.com to discover insightful answers from experts and enthusiasts alike. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.
Sagot :
Option D
- 5x²+8x-12=2x²-x
- 5x²-2x²+8x+x-12=0
- 3x²+9x-12=0
- x²+3x-4=0
Now we can apply quadratic formula to find two zeros
Answer:
[tex]\textsf{D.}\quad5x^2+8x-12=2x^2-x[/tex]
Step-by-step explanation:
Quadratic Formula
[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when}\:ax^2+bx+c=0[/tex]
A linear equation in the form [tex]y=mx+b[/tex] cannot be solved using the quadratic formula, as it is not a quadratic equation.
[tex]\textsf{A.}\quad 4x + 2 = 0[/tex]
This is a linear equation and therefore cannot be solved using the quadratic formula.
[tex]\begin{aligned}\textsf{B.}\quad 3x^2-4&=3x^2-4x\\\implies -4&=-4x\end{aligned}[/tex]
This is a linear equation and therefore cannot be solved using the quadratic formula.
[tex]\textsf{C.}\quad 2x=32[/tex]
This is a linear equation and therefore cannot be solved using the quadratic formula.
[tex]\textsf{D.}\quad5x^2+8x-12=2x^2-x[/tex]
[tex]\implies 3x^2+9x-12=0[/tex]
Therefore, this is a quadratic equation in the form [tex]ax^2+bx+c=0[/tex] and therefore can be solved quadratic formula.
a = 3, b = 9 and c = -12
Inputting these into the quadratic formula and solving for x:
[tex]\begin{aligned}\implies x &=\dfrac{-(9) \pm \sqrt{(9)^2-4(3)(-12)}}{2(3)}\\\\x& = \dfrac{-9 \pm \sqrt{225}}{6}\\\\x& = \dfrac{-9 \pm 15}{6}\\\\x&=\dfrac{6}{6},\dfrac{-24}{6}\\\\x&=1, -4\end{aligned}[/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.