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Akeno performed an experiment in which he rolled a six-sided die and recorded the number it landed on in the following tally chart.

A tally chart. 1 has 6 tally marks, 2 has 2 tally marks, 3 has 5 tally marks, 4 has 6 tally marks, 5 has 5 tally marks, & 6 has 7 tally marks.


Based on the experiment, what is the probability of the die landing on 5?
Enter your answer as a fraction, like this: 42/53

Sagot :

Using the probability concept, it is found that there is a [tex]5/31 = \frac{5}{31}[/tex] probability of the die landing on 5.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, from the experiment, out of 6 + 2 + 5 + 6 + 5 + 7 = 31 marks, 5 landed on 5, hence:

p = 5/31.

[tex]5/31 = \frac{5}{31}[/tex] probability of the die landing on 5.

More can be learned about the probability concept at https://brainly.com/question/14398287

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