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Find the surface area of a square pyramid with side length 3 m and slant height 5 m.

Sagot :

ⲊⲧɑⲅⲊⲏɑᴅⲟᏇidn

Ⲁⲛ⳽ⲱⲉⲅ:

  • 39 m²

Ⲋⲟⳑⳙⲧⳕⲟⲛ :

Information provided with us:

  • Side length ( a ) = 3m
  • Slant height ( l ) = 5m

Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙⳑɑ :

Surface area of square pyramid is given by the sum of areas of all its 4 triangular sides and the square base area. If a is the base side length and l is the slant height , then the surface area of square pyramid is:

‎ㅤ‎‎ㅤ‎ㅤ‎ㅤ‎ㅤ➙ a² + 2al

Ⲧⲏⲉⲅⲉ⳨ⲟⲅⲉ:

‎ㅤ‎ㅤ‎ㅤ➙ A = a² + 2al

‎ㅤ‎ㅤ‎ㅤ➙ A = ( 3 ) ² + 2 × 3 × 5

‎ㅤ‎ㅤ‎ㅤ➙ A = 9 + 30

‎ㅤ‎ㅤ‎ㅤ➙ A = 39m²

~Hence, the surface area of given square pyramid is 39 m².

Semsee45idn

Answer:

39 m²

Step-by-step explanation:

surface area of square based pyramid = [tex]a^2+2al[/tex]

(where [tex]a[/tex] is the side length of the base and [tex]l[/tex] is the slant height)

Given:

  • [tex]a=3[/tex]
  • [tex]l=5[/tex]

⇒ SA = 3² + (2 x 3 x 5) = 39 m²        

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