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Explain why the binomial n2 - 16 is not equal to (n + 8)(n - 8). please helppp due in 10 minutesss

Sagot :

Answer:

see explanation

Step-by-step explanation:

n² - 16 ← is a difference of squares and factors in general as

a² - b² = (a + b)(a - b) , then

n² - 16

= n² - 4²

= (n + 4)(n - 4)

cannot be (n + 8)(n - 8)

= n² - 64

RevyBreezeidn

Answer/Step-by-step explanation:

Let's first solve [tex](n+8)(n-8)[/tex]

Distribute

[tex]n(n-8)+8(n-8)[/tex]

Distribute

[tex]n^2-8n+8(n-8)[/tex]

Distribute

[tex]n^2-8n+64[/tex]

Combine like terms

[tex]n^2-64[/tex]

Therefore n2-16 is not equal to (n+8)(n-8) because (n+8)(n-8) is equal to n^2-64.

[RevyBreeze]

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