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O is the center of the regular nonagon below. Find its perimeter. Round to the nearest tenth if necessary.
17
O

O Is The Center Of The Regular Nonagon Below Find Its Perimeter Round To The Nearest Tenth If Necessary 17 O class=

Sagot :

MrRoyalidn

The perimeter of a nonagon is the sum of its side lengths

The perimeter of the regular nonagon is 840.7 units

How to determine the perimeter

The in-radius of the regular nonagon is given as:

r =17

The perimeter is then calculated as:

[tex]P = \frac{18r}{\tan(pi/9)}[/tex]

Substitute 17 for r

[tex]P = \frac{18 * 17}{\tan(pi/9)}[/tex]

Evaluate the product of 18 and 17

[tex]P = \frac{306}{\tan(pi/9)}[/tex]

Evaluate the quotient

[tex]P =840.7[/tex]

Hence, the perimeter of the regular nonagon is 840.7 units

Read more about perimeters at:

https://brainly.com/question/24571594

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