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Find a line that is perpendicular to y = 2/5x-1 that goes through (3,6)

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Answer:

[tex]\sf y=-\frac{5}{2}x+\frac{27}{2}[/tex]

Step-by-step explanation:

given equation:

[tex]\sf y = \frac{2}{5} x -1[/tex]

using the formula: y = mx + b

Here, we can determine 2/5 is the slope

if perpendicular: -1/m → -1/2/5 → -5/2

using the formula:

[tex]\sf y - y1 = m ( x - x1)[/tex]

[tex]\sf y - 6 = -\frac{5}{2} ( x - 3 )[/tex]

[tex]\sf y - 6 = -\frac{5}{2} x - \frac{15}{2}[/tex]

[tex]\sf y = -\frac{5}{2} x + \frac{15}{2} +6[/tex]

[tex]\sf y=-\frac{5}{2}x+\frac{27}{2}[/tex]

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