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Solve each system using substitution.

y = 2x
6x - y = 8


3x + 5y = 2
x + 4y = -4
Answer for 50 BRAINLIST!!!

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Answer:

[tex](2, 4)\rightarrow\text{First system}[/tex]

[tex](4, -2)\rightarrow\text{Second system}[/tex]

Step-by-step explanation:

First system:

We can substitute 2x for y:

[tex]6x-y=8\\6x-2x=8\\4x=8[/tex]

Divide both sides by 4

[tex]x=2[/tex]

Substitute 2 for x to solve for y:

[tex]y=2x=2(2)=4[/tex]

[tex](x, y)=(2, 4)[/tex]

Second system:

We can isolate x in the second equation by subtracting 4y from both sides:

[tex]x=-4-4y[/tex]

Now, substitute this value for x in the first equation:

[tex]3(-4-4y)+5y=2\\[/tex]


Distribute the 3 to each term in the parentheses:

[tex]3(-4)+3(-4y)+5y=2\\-12-12y+5y=2\\-12-7y=2[/tex]

Add 12 to both sides:

[tex]-7y=14[/tex]

Divide both sides by -7

[tex]y=-2[/tex]

Now, substitute -2 for y to solve for x:

[tex]x=-4-4y=-4-4(-2)=-4+8=4[/tex]

[tex](x, y)=(4, -2)[/tex]

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