Get the information you need with the help of IDNLearn.com's expert community. Find in-depth and trustworthy answers to all your questions from our experienced community members.

Line p contains point (6,-5) and is perpendicular to line q. The equation for line q is
y = 3x + 5.
Write an equation for line p.
Part I: Find the slope of line q. (1 point)
Part II: Find the slope of line p. (Write the negative reciprocal of the slope you found
in Part I.)
I just need the last part!!


Sagot :

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 5 ← is in slope- intercept form

with m = 3

Part 1

slope of line q is 3

Part 11

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{3}[/tex] = - [tex]\frac{1}{3}[/tex] ← slope of line p

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.