Randamalik85idn
Answered

IDNLearn.com offers a comprehensive platform for finding and sharing knowledge. Get prompt and accurate answers to your questions from our community of experts who are always ready to help.

Chord AB is 3cm from the center of a circle, the radius of the circle is 5cm, calculate the length of the chord.​

Sagot :

VirαtKσhliidn

Answer:

[tex]\large{\boxed{\sf Chord = 8cm }}[/tex]

Step-by-step explanation:

First see figure in attachment . As we know that ,Perpendicular from centre of the circle bisects the chord . Hence here ,

  • OC is the perpendicular bisector of chord AB .
  • Let us assume that AC = x , therefore ,

[tex]\sf\qquad\longrightarrow AB = 2AC = 2x [/tex]

Now in ∆OAC , by Pythagoras Theorem , we have ;

[tex]\sf\qquad\longrightarrow (5cm)^2= x^2+(3cm)^2\\ [/tex]

[tex]\sf\qquad\longrightarrow 25cm^2=x^2+9cm^2\\[/tex]

[tex]\sf\qquad\longrightarrow x^2=25cm^2-9cm^2\\[/tex]

[tex]\sf\qquad\longrightarrow x^2=16cm^2\\ [/tex]

[tex]\sf\qquad\longrightarrow \pink{ x = 4cm } [/tex]

Therefore , the length of chord will be ,

[tex]\sf\qquad\longrightarrow AB = 2x \\ [/tex]

[tex]\sf\qquad\longrightarrow AB = 2(4cm)\\[/tex]

[tex]\sf\qquad\longrightarrow \pink{ AB = 8cm } [/tex]

Hence the length of chord is 8cm .

View image VirαtKσhli
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.