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Two students side in carts opposite to one another in a spinning Ferris wheel as shown.
Student A is originally at the bottom of the Ferris wheel while student B is at the top of the Ferris wheel. As the wheel turns, student B comes to the bottom white student A arrives at the top, as shown. The Ferris wheel spins at a constant speed so the two students are traveling with constant speed. Students A and B have masses ma and mb, respectively. The Ferris wheel has a radius R. What is the magnitude of the TOTAL work done on student A in moving from the bottom to the top of the Ferris wheel? The total work is the sum of the work done by all the forces on the body; i.e. Wtotal = sum(Fd). Neglect air resistance.
Also, what is the sign of the work done on student B by the Ferris wheel in moving from the top to the bottom?

Sagot :

Okpalawalter8idn

Net work done  on student B by the Ferris wheel in moving from the top to the bottom  is mathematically given as

net work done on A =0.

Net work done  

Generally the equation for the work energy theorem is mathematically given as

net work done on A = change in kinetic energy of A.

Where, angular velocity is constant.

change in kinetic energy = 0.

Hence, from work energy theorem,

net work done on A =0.

For more information on work

https://brainly.com/question/756198

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