IDNLearn.com makes it easy to find accurate answers to your specific questions. Get the information you need from our community of experts who provide accurate and thorough answers to all your questions.
Sagot :
Answer:
cos²Θ
Step-by-step explanation:
simplify the expression using the identities
tanΘ = [tex]\frac{sin0}{cos0}[/tex]
cos2Θ = 1 - 2sin²Θ
cos²Θ = 1 - sin²Θ
then
tanΘ × sinΘ × cosΘ + cos2Θ
= [tex]\frac{sin0}{cos0}[/tex] × sinΘ × cosΘ + 1 - 2sin²Θ ( cancel cosΘ on numerator/ denominator )
= sinΘ × sinΘ + 1 - 2sin²Θ
= sin²Θ + 1 - 2sin²Θ
= 1 - sin²Θ
= cos²Θ
Answer:
[tex]\cos^2(\theta)[/tex]
Step-by-step explanation:
Trig identities used:
[tex]\cos(2\theta)=\cos^2(\theta)-\sin^2(\theta)[/tex]
[tex]\tan(\theta)=\dfrac{\sin(\theta)}{\cos(\theta)}[/tex]
Therefore,
[tex]\tan(\theta)\times\sin(\theta)\times\cos(\theta)+\cos(2\theta)[/tex]
[tex]=\dfrac{\sin(\theta)}{\cos(\theta)}\times\sin(\theta)\times\cos(\theta)+\cos(2\theta)[/tex]
[tex]=\sin^2(\theta) +\cos(2\theta)[/tex]
[tex]=\sin^2(\theta) +\cos^2(\theta)-\sin^2(\theta)[/tex]
[tex]=\cos^2(\theta)[/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.