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Suppose a 10.0 mL sample of an unknown
concentration of HCI is pipetted into a 625 mL
volumetric flask, and the flask is filled with distilled
water to the mark. If the concentration of the final
solution is determined to be 0.004 M. what was the
concentration of HCI?

Sagot :

The concentration of HCl is equal to 2.54mol/L.

Mole calculation

To solve this question, one must use the molarity calculation, which corresponds to the following expression:

                                               [tex]M = \frac{mol}{v}[/tex]

Thus, to find the molarity of the sample, the following calculations must be performed:

[tex]V_f = 10ml + 625ml = > 635ml[/tex]

                                              [tex]\frac{0.004mol}{xmol} =\frac{1000ml}{635ml}[/tex]

                                                 [tex]x = 0.00254 mol[/tex]

So, 0.00254 moles were added per 10ml, so we can do:

                                              [tex]\frac{0.00254mol}{xmol}= \frac{10ml}{1000ml} \\x = 2.54mol/L[/tex]

So, the concentration of HCl is equal to 2.54mol/L.

Learn more about mole calculation in: brainly.com/question/2845237

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