Answered

Get comprehensive answers to your questions with the help of IDNLearn.com's community. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

One more bulb is added to the circuit and the location of the switch is changed. The new circuit is shown in the figure. (figure 2) bulbs a, b, c, and d are identical and the switch is an ideal conductor. How does closing the switch in the figure affect the potential difference?.

Sagot :

Okpalawalter8idn

The potential difference across a, b is mathematically given as

E_a=0.5

E_b= 0

Potential difference across a, b

Generally the equation for the switch when closed   is mathematically given as

[tex]Rc=Ra+\frac{Rb}{2}[/tex]

Therefore

Rc=3R/2

Where

[tex]va=2R/3R *e[/tex]

va=2/3* e

vb=vc=(2/3e)

When switch is closed

va=e

vb=vc=0

Therefore potential difference across a is

[tex]E_a=\frac{e-2/3e}{2/3e}[/tex]

E_a=1/2

E_a=0.5

And potential difference across b is

E_b= 0

For more information on Voltage

https://brainly.com/question/14883923

We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.