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Tim is driving his car that has a mass of 420-kg and a velocity of 22m/s East. As he is driving a 120-kg deer is traveling North. The car and deer collide and stick together.
(A) If after the crash they moved at an angle of 22 degrees how fast was the deer going?
(B) what is their final velocity with the direction after the collision?

Sagot :

Onyebuchinnajiidn

The initial velocity of the deer is 31.11 m/s.

Their final velocity with the direction after the collision is 0.21 m/s

Initial momentum of the car and deer

The initial momentum of the car and the deer is calculated as follows;

Pi(car)x = 420(22)

Pi(deer)y = 120v

[tex]tan \theta = \frac{P_y}{P_x} \\\\tan (22) = \frac{120v}{420(22)} \\\\v = \frac{tan(22) \times 420(22)}{120} \\\\v = 31.11 \ m/s[/tex]

Resultant momentum of the system

[tex]P = \sqrt{P_y^2 + P_x^2} \\\\P = \sqrt{(420 \times 22) + (120 \times 31.11)} \\\\P = 113.89 \ kgm/s[/tex]

Final velocity of the system

v = P/(m₁ + m₂)

v = (113.89) / (420 + 120)

v = 0.21  m/s

Learn more about conservation of linear momentum here: https://brainly.com/question/7538238

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