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f (x) = 2 (x + 1)^2 - 1

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Answer:

Equation: y = x²

  • (-2, 4)
  • (0, 0)
  • (2, 4)

Equation: f(x) = 2(x + 1)² - 1

  • (-2, 1)
  • (0, 1)
  • (2, 17)

Step-by-step explanation:

Equation: y = x²

  • when x = -2, y = (-2)² = 4 ⇒ (-2, 4)
  • when x = 0, y = (0)² = 0 ⇒ (0, 0)
  • when x = 2, y = (2)² = 4 ⇒ (2, 4)

Equation: f(x) = 2(x + 1)² - 1

f(-2) = 2(-2 + 1)² - 1

      = 2(-1)² - 1

      =2(1) - 1

     = 1

Therefore, (-2, 1)

f(0) = 2(0 + 1)² - 1

     = 2(1)² - 1

      =2(1) - 1

     = 1

Therefore, (0, 1)

f(2) = 2(2 + 1)² - 1

     = 2(3)² - 1

      =2(9) - 1

     = 17

Therefore, (2, 17)

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