Dave4963idn
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find how the circles x^2+y^2+2x+6y=39 and x^2+y^2-4x-2y+1=0​

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Step-by-step explanation:

x² + y² + 2x + 6y = 39

( x + 1)² - 1 + ( y + 3)² - 9 = 39

( x + 1)² + ( y + 3)² - 10 = 39

(x + 1)² + (y + 3)² = 49

radius= √49 = 7

center = ( -1 , -3)

x² + y² - 4x - 2y + 1 = 0

(x - 2)² - 4 + (y - 1)² -1 + 1 = 0

(x - 2)² + (y - 1)² = 4

radius = √4 = 2

center = (2 , 1)

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