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How many grams of NaCl are needed to prepare a 1.0 m solution using 250 g of solvent?
A 1 M solution corresponds to 1 mole of the solute (here, sodium chloride, NaCl) in 1 L of solvent (here probably water). Since the question calls for only making 250 mL, or 1/4 of a L, only 1/4 or 0.25 mol will be required. The molecular weight of NaCl is 58.44 g/mol so you will need:
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