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Sagot :
Hello.
First of all, let the number be t.
8 times t can be written like this:
[tex]\mathrm{8t}[/tex]
Notice that the number is before the variable and the times sign (×) is not there.
We can write it as 8×t, but we usually write it as 8t.
The sum of means we add:
8t+21
Now, "less than" is "<" :
[tex]\mathrm{8t+21 < -16}[/tex]
Therefore, the answer is
[tex]\mathrm{8t+21 < -16}[/tex]
I hope it helps.
Have a nice day.
[tex]\boxed{imperturbability}[/tex]
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