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The equation P= 21 + 2w models the perimeter, P, of a rectangle with a length of / units and a width of w units.
A rectangle has perimeter of 60 units and a length that is double its width.
What is the width in units
of the rectanale?

Sagot :

Fieryanswererftidn

Answer:

width = 10 units and length = 20 units

Step-by-step explanation:

Let the width be w

so Length will be 2w

using the rectangle formula:

[tex]\sf Perimeter \ of \ rectangle= 2L + 2W[/tex]

[tex]\sf 60= 2(2w) + 2w[/tex]

[tex]\sf 60= 4w + 2w[/tex]

[tex]\sf 60= 6w[/tex]

[tex]\sf w = 10 \ units[/tex]

Find length:

[tex]\sf length = 2w[/tex]

[tex]\sf length = 2(10)[/tex]

[tex]\sf length = 20 \ units[/tex]
With = 10 units Length = 20
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