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Find the equation of the line containing the point (-1, 5) and having a slope: -2

Sagot :

Step-by-step explanation:

Slope-intercept form:

[tex]y=mx+b[/tex]

m = slope

b = y-intercept

The slope is given; -2.

We have to figure out what the y-intercept is.

The y-intercept is where the line crosses the y-axis, or when x = 0.

Given the point, (-1, 5), we can determine what the y-intercept is with the slope.

The slope is describing that per every x, y decreases by 2.

-1 + 1 = 0 (x)

5 - 2 = 3 (y)

3 is the y-intercept

Substitute the slope and the y-intercept in the slope-intercept form equation:

[tex]\boxed{y=-2x+3}[/tex]