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Question 1
Let f(x)=x3−4x2+6 and g(x)=f(−x)+4. Write a rule for g.


Sagot :

Answer

  g(x)= - x3−4x²+10

Step-by-step explanation:

hello

Let f(x)=x3−4x2+6 so    g(x)=f(−x)+4.

  g(x)=(-x)3−4(-x)²+6+4

  g(x)= - x3−4x²+10 is  a rule for g     be cause (-x)3=- x3 and (-x)²=x²