Gotenks99idn
Answered

Find expert answers and community support for all your questions on IDNLearn.com. Our community provides accurate and timely answers to help you understand and solve any issue.

For the following reaction, 3.07 grams of sulfur dioxide are mixed with excess water. The reaction yields 2.84 grams of sulfurous acid (H₂SO3).

sulfur dioxide (g) + water (L)→ sulfurous acid (H₂SO3) (g)

What is the theoretical yield of sulfurous acid (H₂SO3)? 3.93grams

What is the percent yield for this reaction?72.2%​

For The Following Reaction 307 Grams Of Sulfur Dioxide Are Mixed With Excess Water The Reaction Yields 284 Grams Of Sulfurous Acid HSO3sulfur Dioxide G Water L class=

Sagot :

7142ja99idn

3.93 and 72.2%

Explanation:

Theoretical Yield:

[tex]3.07 \: g \: SO₂ \times \frac{1 \: mol \: SO₂}{64.07g \: SO₂} \times \frac{1 \: mol \: H₂SO₃}{1 \: mol \: SO₂} \times \frac{82.09 \: g \: H₂SO₃}{1 \: mol \:H₂SO₃ } = 3.933 \: g \: H₂SO₃[/tex]

Percent Yield:

[tex] \frac{2.84 \: g}{3.993 \: g} \times 100 = 72.2\%[/tex]

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.