The base is 30cm & height is 40cm
Step-by-step explanation:
Height is 10+ the base
H is (x + 10)
B is x
(x is a variable - representing an unknown number)
A= bxh
1200 = x x (x+10)
(expand brackets)
1200 = x^2 + 10x
- 1200 (both side)
Now we've got to factorise to find the value of x :
x^2 + 10x - 1200 = 0
x to get - 1200
+ to get 10
40 x - 30= - 1200
40 + - 30 = 10
Slipt 10x into 40x & - 30x, then, factorise:
x^2 + 10x - 1200
x^2 + 40x - 30x - 1200
x(x + 40). - 30 (x + 40)
(x - 30)(x+40) =0
(x-30) =0
+30
x = 30
(x+40) =0
-40
x = - 40
Thus, x is going to be 30 because we can't have a negative length (I.e., - 40.)
So, the base is 30cm & height is 40cm
(30+10, giving them a difference of 10cm)
Check:
A= bxh
= x x (x+10)
= 30 x (30+10)
= 30 x (40)
= 1200 (square feet)
Hope this helps!
