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Sagot :
This question involves the concepts of wave speed, wavelength, and frequency.
The frequency of the wave in seawater will be "2.68 Hz".
FREQUENCY
The relationship between speed, wavelength, and frequency of the wave can be given by the following formula:
[tex]v=f\lambda\\\\\lambda =\frac{v}{f}[/tex]
Here, the wavelength of the wave is a constant property. Therefore,
[tex]\frac{v_1}{f_1}=\frac{v_2}{f_2}[/tex]
where,
- v₁ = speed of the wave in the rock = 3950 m/s
- v₂ = speed of the wave in the seawater = 1500 m/s
- λ = wavelength = 560 m
- f₁ = frequency of the wave in the rock = [tex]f_1=\frac{v_1}{\lambda}=\frac{3950\ m/s}{560\ m} = 7.05\ Hz[/tex]
- f₂ = frequency of the wave in the seawaater = ?
Therefore,
[tex]\frac{3950\ m/s}{7.05\ Hz}=\frac{1500\ m/s}{f_2}\\\\f_2=\frac{(1500\ m/s)(7.05\ Hz)}{3950\ m/s}[/tex]
f₂ = 2.68 Hz
Learn more about wavelength here:
https://brainly.com/question/7143261
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