Get the best answers to your questions with the help of IDNLearn.com's experts. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.
Sagot :
This question involves the concepts of wave speed, wavelength, and frequency.
The frequency of the wave in seawater will be "2.68 Hz".
FREQUENCY
The relationship between speed, wavelength, and frequency of the wave can be given by the following formula:
[tex]v=f\lambda\\\\\lambda =\frac{v}{f}[/tex]
Here, the wavelength of the wave is a constant property. Therefore,
[tex]\frac{v_1}{f_1}=\frac{v_2}{f_2}[/tex]
where,
- v₁ = speed of the wave in the rock = 3950 m/s
- v₂ = speed of the wave in the seawater = 1500 m/s
- λ = wavelength = 560 m
- f₁ = frequency of the wave in the rock = [tex]f_1=\frac{v_1}{\lambda}=\frac{3950\ m/s}{560\ m} = 7.05\ Hz[/tex]
- f₂ = frequency of the wave in the seawaater = ?
Therefore,
[tex]\frac{3950\ m/s}{7.05\ Hz}=\frac{1500\ m/s}{f_2}\\\\f_2=\frac{(1500\ m/s)(7.05\ Hz)}{3950\ m/s}[/tex]
f₂ = 2.68 Hz
Learn more about wavelength here:
https://brainly.com/question/7143261
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.