Answered

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Which is the equation of the line, in point-slope form, that has a slope of 5 and passes through the point (-2, 4)?


y − 4 = 5(x−2)


y − 2 = 5(x+2)


y − 2 = −5(x−4)


y − 4 = 5(x+2)

Sagot :

[tex](\stackrel{x_1}{-2}~,~\stackrel{y_1}{4})\qquad \qquad \stackrel{slope}{m}\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{5}(x-\stackrel{x_1}{(-2)})\implies y-4=5(x+2)[/tex]

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