Answer:
Step-by-step explanation:
By the law of Sines,
[tex]\frac{\sin 88^{\circ}}{26}=\frac{\sin C}{21}\\\sin C=\frac{21 \sin 88^{\circ}}{26}\\C=\sin^{-1} \left(\frac{21 \sin 88^{\circ}}{26} \right) \approx 54^{\circ}[/tex]
However, it follows that [tex]C \approx 126^{\circ}[/tex] must also be a solution.
