Answer:
we know that
area of the circle is equal to
A=pi* r^{2}A=pi∗r
2
solve for r
r= \sqrt{ \frac{A}{pi}}r=
pi
A
for A=60 cm^{2}60cm
2
r= \sqrt{ \frac{60}{pi}} cmr=
pi
60
cm
we know that
\begin{gathered} \sqrt{60} = \sqrt{ 2^{4}*3*5} \\ =2 \sqrt{15} \end{gathered}
60
=
2
4
∗3∗5
=2
15
so
\sqrt{ \frac{60}{pi}}=2 \sqrt{ \frac{15}{pi}}
pi
60
=2
pi
15
2 \sqrt{ \frac{15}{pi}}=2 \frac{ \sqrt{15}}{ \sqrt{pi}} * \frac{ \sqrt{pi}}{ \sqrt{pi}}2
pi
15
=2
pi
15
∗
pi
pi
=2 \frac{ \sqrt{15pi}}{pi} cm=2
pi
15pi
cm
the answer is
2 \frac{ \sqrt{15pi}}{pi} cm2
pi
15pi
cm
