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A 5.00 g projectile has a velocity of 255 m/s right. Find the force to stop this projectile in 1.45s.

Sagot :

The10legendgameridn

Explanation:

The X-component of the velocity = Vcosx. Where, V = magnitude of the velocity. The x component of velocity will depend on the diagram. It the angle is measured from the x-axis which is considered the horizontal then Vx = Vcos(theta). The magnitudes of the components of velocity v → are v x = v cos θ and v y = v sin θ , v x = v cos θ and v y = v sin θ , where v is the magnitude of the velocity and θ is its direction relative to the horizontal, as shown in Figure 4.12. Derivation of the Trajectory Formula.

y = refers to the vertical position of the object in meters. x = refers to the horizontal position of the object in meters. Horizontal velocity component: Vx = V * cos(α)

Vertical velocity component: Vy = V * sin(α)

Time of flight: t = [Vy + √(Vy² + 2 * g * h)] / g.

Range of the projectile: R = Vx * [Vy + √(Vy² + 2 * g * h)] / g.

Maximum height: hmax = h + Vy² / (2 * g)

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