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Answer:
Step-by-step explanation:
hello :
you have this system : y=2x²-12x+20
y=2
means : 2x²-12x+20 =2
2x²-12x+20-2 =0
2x²-12x-18 =0 a=2 and b= -12 and c= -18
delta = b²-4ac
delta = (-12)²-4(2)(-18)
delta = 0
X1 =X2 = -b/2a =12/4 =3
the solution point is : (3 ; 2)
The graph of the solution point (3, 2) for given system of equations [tex]y=2x^{2}-12x+20,~y=2[/tex] is shown below.
"It is s et of equations for which we find the common solution."
For given question,
We have been given a system if equations.
[tex]y=2x^2-12x+20\\\\y=2[/tex]
From given system of equations,
[tex]2x^2-12x+20=2[/tex]
We solve above quadratic equation.
[tex]2x^2-12x+20=2[/tex]
From given system of equations,
[tex]2x^{2}-12x+20=2\\\\x^2-6x+9=0\\\\(x-3)^2=0\\\\x=3[/tex]
This means at point (3, 2) is the solution of the given system of equations [tex]y=2x^{2}-12x+20,~y=2[/tex]
The graph of the solution point (3, 2) for given system of equations [tex]y=2x^{2}-12x+20,~y=2[/tex] is shown below.
Learn more about system of equations here:
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