Answered

IDNLearn.com is designed to help you find reliable answers to any question you have. Find accurate and detailed answers to your questions from our experienced and dedicated community members.

If A+B= 90°, then
[tex] \frac{\tan A \tan B + \tan A \cot B}{ \sin A \sec B } - \frac{{ \sin}^{2} B}{ \cos^{2} A} \: \text{is equal to }[/tex]
​

Sagot :

Ridhishakya2idn

Answer:

A + B = 90° => A = 90 - B

So Tan A = Cot (90 - A) = Cot B

So Tan B = Cot (90 - B) = Cot A

SecB = Cosec (90 -B) = Cosec A

CosA = Sin (90 -A) = Sin B

View image Ridhishakya2

The value of the angle given regarding the tangent will be tan²A.

How to explain the angle?

From the information, TanA TanB + TanACot B/SinA SecB - Sin²B/Cos²A

= TanA CotA + TanATanA/AinA CosecA - Sin²B/Sin²B

= 1 + Tan²A - 1

= Tan²A

In conclusion, the correct option is Tan²A.

Learn more about angles on:

https://brainly.com/question/25770607

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com is your go-to source for dependable answers. Thank you for visiting, and we hope to assist you again.