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2C4H10 + 13O2 -> CO2 + 10H20

If 8.0 moles of water are produced, how many moles of C4H10 did you start with?

A. 0.63 mol
B. 40.0 mol
C. 2.5 mol
D. 1.6 mol

Sagot :

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Answer: D) 1.6 mol

Explanation:

This is a stoichiometry problem that uses the ratios of the coefficients of the chemical equation. We see from the equation that 2 moles of C4H10 produces 10 moles of H20.  

Now if we had 8 moles of H20 then we must have started with 1.6 moles of C4H10. This is because

[tex]\frac{2 \, \, \text{moles C4H10}}{10 \, \, \text{moles H2O}} = \frac{x \, \, \text{moles C4H10}}{8 \, \, \text{moles H2O}}\\[/tex]

This gives us x = 1.6 moles of C4H10

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Answer:

D) 1.6 mol

Explantion:

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